Shell Programming and Scripting

Hello:
I wrote a sed statement that is inserting 3 variables at the beginning of each record in a comma-delimited file:

for FILE in *gnrc_lkup.csv
do
c=`echo $FILE | cut -c1-3`
d=`grep $c $RTLIST | cut -c4-6`
e=`grep $c $RTLIST | cut -c7`
f=`grep $c $RTLIST | cut -c8`
sed -e 's/^/'$d','$e','$f',/' < $FILE > $FILE.new
done

However, after further testing, I noticed that the
last record is being removed. Can someone tell me what part of the sed statment above would be doing this and how it can be corrected?

Any input is appreciated.
Thank you,
Brett

Is there a newline at the end of the file?

If not, it is not a valid text file, and sed only works with text files.

Thank you cfajohnson for the reply.

There is no newline at the end. I think
during editing it got removed. Even though this was not a valid text file by your definition, do you know why the sed command would work
on all but the last data record which it removed? Your input is appreciated. Thanks, Brett

So put a newline at the end and its now a "text" file and it should work.

I would ASSume that it looks for a "newline" before processing the line, so if its not there it excludes the whole line.

Thanks again for the reply cfajohson
Thanks ikon for replying.