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selective printing awk

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# 1  
Old 07-02-2008
selective printing awk
Hi there

my file looks like this

1 a b c d e f
2 a b b c d e f f g h e t t
3 a c b d e f
4 a b c

i want to print the line which has the fields containing ONLY a b c, in this case the line 4.

How can i awk it !!!?

Many Thanks in advance!
# 2  
Old 07-02-2008
Assuming your 1 2 3 4 are not part of the file
Code:
awk '$0=="a b c" ' file

# 3  
Old 07-02-2008
Quote:
Originally Posted by jim mcnamara
Assuming your 1 2 3 4 are not part of the file
Code:
awk '$0=="a b c" ' file

Thanks but it doesnt help...may be am wrong in the question.

I reframe the question:

John a b c d e f
Bob a b c
Fred b c a
Tom a c d f e

i want to print the lines Bob and Fred which contain the "a b c"
# 4  
Old 07-02-2008
Code:
awk '/a b c/' file

Regards
# 5  
Old 07-02-2008
nawk -f saint.awk myFile

saint.awk:
Code:
BEGIN {
  str="a b c"
  n=split(str, strA, FS)
  for(i=1; i<=n; i++) {
    strA[strA[i]]
    delete strA[i]
  }
}
{
  for(i=2; i<=NF; i++)
    if (!($i in strA)) next

  print
}

YMMV depending on what you mean by 'a b c'.
Last edited by vgersh99; 07-02-2008 at 02:17 PM..
# 6  
Old 07-02-2008
Quote:
Originally Posted by Franklin52
Code:
awk '/a b c/' file

Regards
It works but it prints only the line containing a b c in the given order and not if the line contains a b c in different order
# 7  
Old 07-02-2008
Quote:
Originally Posted by saint2006
John a b c d e f
Bob a b c
Fred b c a
Tom a c d f e

i want to print the lines Bob and Fred which contain the "a b c"
Code:
awk '/Bob/ || /Fred/ && /a/ && /b/ && /c/'  file
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