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command line arg issue with awk

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# 1  
Old 05-22-2008
Data command line arg issue with awk
Hi friends,

I am trying to pass input from command line and trying to print that column values. (FYI: I am using ksh) My code goes like this...

#!/bin/sh
column=$1
awk '{print $'$column'}'

I execute using command like this --> ls -l | file_name parameter

Hope I am clear with my problem. The error I am getting is something like this,
Syntax Error The source line is 3.
The error context is
awk >>> ' <<<
awk: 0602-500 Quitting The source line is 3.

I tried even removing quotes, but in vain. please help me.
Thanks in advance,
Divya
# 2  
Old 05-22-2008
Quote:
Originally Posted by divzz
Hi friends,

I am trying to pass input from command line and trying to print that column values. (FYI: I am using ksh) My code goes like this...

#!/bin/sh
column=$1
awk '{print $'$column'}'

I execute using command like this --> ls -l | file_name parameter

Hope I am clear with my problem. The error I am getting is something like this,
Syntax Error The source line is 3.
The error context is
awk >>> ' <<<
awk: 0602-500 Quitting The source line is 3.

I tried even removing quotes, but in vain. please help me.
Thanks in advance,
Divya
#!/bin/sh
column=$1
awk -v x=$column '{print $x}'


Hope this works
# 3  
Old 05-23-2008
MySQL
Quote:
Originally Posted by elthox
#!/bin/sh
column=$1
awk -v x=$column '{print $x}'


Hope this works

Thanks a lot buddy, it works Smilie Smilie Smilie
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