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grep with variable

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# 1  
Old 05-14-2008
grep with variable
Hi, I can't get this script to work (returns 0, should return 3):

Code:
$ cat A.lst | \
while read LINE
do
        echo "$LINE"
        grep -c "$LINE" B.tmp
done> > > > >
Socket
0
$

but in contrast this one works fine (returns 3 as expected):

Code:
$  LINE=Socket
$ grep -c $LINE B.tmp
3
$


Note: A.lst contains one line with a string: Socket
B.tmp contains 3 lines with strings: Socket

Thank you!
# 2  
Old 05-14-2008
Whitespace around the "Socket" in A.lst?
# 3  
Old 05-14-2008
No, there is not. Even if there is it should work as Socket has spaces around in B.tmp file:


Code:
$ LINE=" Socket "
$ grep -c $LINE B.tmp
$ 3

# 4  
Old 05-14-2008
Check with od.
Hi.

Try od -c A.lst , I'm also of the opinion that there's something funky in it.

Also, in your last code example, you didn't replicate the quotes around the grep pattern. Those make a large difference.
# 5  
Old 05-14-2008
Why not:

Code:
grep -c -f A.list B.tmp

Regards
# 6  
Old 05-14-2008
Thanks for your help, it works after I did this:

Code:
$  od -c A.lst
0000000   S   o   c   k   e   t  \r  \n
0000010
$ dos2unix A.lst A.lst
$  od -c A.lst
0000000   S   o   c   k   e   t  \n
0000007

The file was created under Win OS.
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