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Return code of background process

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# 1  
Old 04-06-2008
Return code of background process
Hi,

I have a process that I run in the background that looks like this

Code:
${BASEDIR}/ksh/sqler.ksh   ${compnames003[$i]} &

and I would like to get the return code of the sqler.ksh script.

so my code is like this

Code:
${BASEDIR}/ksh/sqler.ksh   ${compnames003[$i]} &

retcode=$?

but this always returns 0 becuase the last statment it run was the & so is there a way to get the return code of the sqler script rather than the return code of the background process.

If I remove the background processing it works..

so

Code:
${BASEDIR}/ksh/sqler.ksh   ${compnames003[$i]}

retcode=$?

works but its not running in the background

Thanks
# 2  
Old 04-06-2008
The return code can only be reaped when the process finishes. Have a look at the wait command. (You will want to wait on that specific process; you get its process ID in $! when you have just started it.)
# 3  
Old 04-06-2008
Hey era,

I was using wait but without the pid, I just literally had "wait" directly underneath.

but now I've changed it to waid for the pid and its now returning the failure code! Smilie

Out of interest is the reason it only returns 0 because it doesn't know what process your referring to if you just use wait witout the pid?

Thanks for the help.
# 4  
Old 04-06-2008
Code:
bash$ help wait
wait: wait [n]
    Wait for the specified process and report its termination status.  If
    N is not given, all currently active child processes are waited for,
    and the return code is zero.  N may be a process ID or a job
    specification; if a job spec is given, all processes in the job's
    pipeline are waited for.

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