How to get BASH to interpret pipes in a string correctly?
In a BASH library I'm creating, I have two functions that look like:
Code:
function check_process {
PIDFILE=$1
if [ -f $PIDFILE ]; then
PID=`cat $PIDFILE`
if [ ! "$PID" == "" ] && [ -d "/proc/$PID" ]; then
return 1
fi;
fi;
return 0
}
function fork_process {
CMD=$1
PIDFILE=$2
if check_process $PIDFILE; then
$CMD &
echo $! > $PIDFILE
echo "new pid in $PIDFILE on `date`" >> $LOG
fi;
}
Which I use to launch, keep track of the PID, and prevent duplicates of any process in a system independent manner (there exists utilities like start-stop-daemon and startproc on different linux flavors, but they are not universal).
So if I want to use it to track a process over an SSH connection, I could do something like:
This would check the file my_process.pid and make sure that the process ID is not already running before going ahead to run the SSH connection and fork it in the background, while saving the new PID in the pid file.
will not work, because BASH will interpret the '|' character literally and not as a pipe. Is there a way to force BASH to interpret '|' as a pipe even when it is in a string?
I put the "eval" operator in my fork_process function like this:
Code:
function fork_process {
CMD=$1
PIDFILE=$2
if check_process $PIDFILE; then
eval "$CMD &"
echo $! > $PIDFILE
echo "new pid in $PIDFILE on `date`" >> $TAILER_LOG
fi;
}
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