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display result from user input

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# 1  
Old 01-31-2008
display result from user input
how can i only display the result according to user input?

For example:
i have a data file(in the attachement), when the user enter "1" it will only display whole records with pid from the data file matches to the users entered.
tes.txt (198 Bytes) 
# 2  
Old 01-31-2008
MySQL Try this....
Try the below code.
Code:
echo "Enter the PID :"
read pid
linenum=`cat tes.txt | tr -s " " "|" | cut -d"|" -f2 |grep -n $pid`
cat tes.txt | head -$linenum | tail -1

Its giving the expected results.


==========
Thanks,
Karthikeyan.
==========
# 3  
Old 01-31-2008
hi Karthikeyan_113! i have error when i run the code.

error shown:
head: unrecongonized option `-:'
# 4  
Old 01-31-2008
Does it have to be awk/ksh? Can you use perl?
# 5  
Old 01-31-2008
Code:
awk 'BEGIN{
 printf "%s : " ,"What Pid"
 getline pid <"-" 
}
$1==pid'  "file"

# 6  
Old 01-31-2008
Quote:
Originally Posted by KevinADC
Does it have to be awk/ksh? Can you use perl?
you could just post your Perl solution. If OP wants a Perl solution, he will use it.
# 7  
Old 01-31-2008
Edit: Do not try this code, it's got a couple of errors. See below for corrected version.


Quote:
Originally Posted by ghostdog74
you could just post your Perl solution. If OP wants a Perl solution, he will use it.
You're right mate. I am not sure what he wants printed out, the whole line or just part of the data, but this prints the whole line associated with the PID number:

Code:
use strict;
use warnings;
print "Enter the PID :"
my $pid = <STDIN>;
chomp $pid;
open (IN , "tes.txt");
while (<IN>) {
   print if (/^\s*$pid\s/); 
   last;
}
close IN;
exit;

Last edited by KevinADC; 01-31-2008 at 06:43 AM..
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