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Searching for + sign in a string using awk

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# 1  
Old 01-10-2008
Searching for + sign in a string using awk
Hi All,

My query is:
I have string say xyz+ how to determine that whether it ends with a + sign or not using awk command.
# 2  
Old 01-10-2008
Quote:
Originally Posted by satyajit2512
Hi All,

My query is:
I have string say xyz+ how to determine that whether it ends with a + sign or not using awk command.
Code:
# awk '/\+$/' file

# 3  
Old 01-11-2008
sed is easy to do such thing
Try this one:

Code:
sed -n '/+$/p' a

# 4  
Old 01-11-2008
quick query for ghostdog
Bro,

wudnt the code that u mentioned search for "xyz+" sting only if it is at the end of a line ? pls correct me if I am wrong

what if the string which has to be searched happens to be in the middle of a line. like
asd sdvdh dfh "xyz+" shfks dfbv
# 5  
Old 01-11-2008
Quote:
Originally Posted by GRUBBERR
Bro,

wudnt the code that u mentioned search for "xyz+" sting only if it is at the end of a line ? pls correct me if I am wrong
yes only at the end of a string, as OP requested
Quote:
what if the string which has to be searched happens to be in the middle of a line. like
asd sdvdh dfh "xyz+" shfks dfbv
a little modification then, but the regexp remains
Code:
...
 for ( i=1;i<=NF;i++) {
  if ( $i ~ /+$/ ) {
    # do something
  }
 }
..

# 6  
Old 01-11-2008
Shorter one:

Code:
> echo "asd sasa+ sd+lvdh dfh xyz+ shfks dfbv ddfd+\c"|awk 'match($0,/\+$/)' RS=" "       
sasa+
xyz+
ddfd+

Or:

Code:
> echo 'asd sasa+ sd+lvdh dfh xyz+ shfks dfbv ddfd+'|awk 'gsub(/\n/," ");match($0,/\+$/)' RS=" " 
sasa+
xyz+
ddfd+

Or:
Code:
> echo "asd sasa+ sd+lvdh dfh xyz+ shfks dfbv ddfd+"|awk 'gsub(/\n/," ");index($0,"+") == (length) ' RS=" "                       
sasa+
xyz+
ddfd+

Or:
Code:
> echo "asd sasa+ sd+lvdh dfh xyz+ shfks dfbv ddfd+\c"|awk 'index($0,"+") == (length) ' RS=" "               
sasa+
xyz+
ddfd+

Last edited by Klashxx; 01-11-2008 at 05:43 AM.. Reason: Another option added.
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