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stripping leftmost characters from string

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# 1  
Old 11-01-2007
stripping leftmost characters from string
Hi there, if i have some strings ie



test_324423
test_242332
test_767667

but I only want the number part (the bolded bit) how do I strip the leftmost 5 characters from the output so that i will have just

324423
242332
767667

any help would be greatly appreciated
Gary
# 2  
Old 11-01-2007
Code:
[yogeshs@PS0814 htdocs]$ echo $str
test_324423
[yogeshs@PS0814 htdocs]$ echo $str | cut -d "_" -f 2
324423
[yogeshs@PS0814 htdocs]$

# 3  
Old 11-01-2007
in bash
Code:
# v=test_324423
# echo ${v#*_}
324423

# 4  
Old 11-01-2007
Quote:
Originally Posted by ghostdog74
in bash
Code:
# v=test_324423
# echo ${v#*_}
324423

This solution is also valid in ksh



Jean-Pierre.
# 5  
Old 11-01-2007
Quote:
Originally Posted by aigles
This solution is also valid in ksh
i see, thanks. I don't use ksh much.
# 6  
Old 11-02-2007
that great, thanks guys
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