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Shell Programming and Scripting

to print number one less than actual number

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# 1  
Old 09-06-2007
to print number one less than actual number
suppose we have a file which contains
34
45
56
77
55
66
54
67

so output shud be like
33
44
55
76
54
65
53
66
# 2  
Old 09-06-2007
file_no's content are
34
45
56
77
55
66
54
67


tempfile=file_no
for number in `cat $tempfile`
do
number=$((number-1))
echo $number
done
# 3  
Old 09-06-2007
Code:
zsh 4.3.4% cat file
34
45
56
77
55
66
54
67
zsh 4.3.4% eval printf "%d\\\n" $(printf "\$((%d-1)) " $(<file))
33
44
55
76
54
65
53
66

or:

Code:
zsh 4.3.4% awk '$1=$1-1' file
33
44
55
76
54
65
53
66

# 4  
Old 09-06-2007
or you can do something like this

for line in `cat $file`
do
line=`expr $line - 1`
echo $line
done

Thanks
Namish
# 5  
Old 09-06-2007
Hey please try this one,

awk ' { printf ("%d\n", $0-1) } ' <<File Name>>
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