Shell Programming and Scripting

Hi

I want to delete first five and last five lines in text files without opening the file and also i want to keep the same file name for all the files.

Thanks in advance!!!

Ragav

Code:

# count=`wc -l file|cut -f1 -d" "`
# more +6 file | head -$(( count-5 ))

should that not be

tail +6 file| head -$(( count-10 ))

to discard top 5 and bottom 5

more +num and tail +num does the same thing. yes you are correct. It should be -10 instead of -5.

Hi,

This one is used to delete certain number of line from the head and end of file in a given direcotory.

Hope it is useful for you.

Hi,

I tried with ur script.Its giving error msg as follows:

xpr:error opening "1, " for input
no such file or directory.

I have tried with following script (assume i have A.txt,B.txt in dir path):

echo "ur dir path:"
read dirp
cd $dirp
for i in *
do
awk 'FNR>5' $i > $i.new
done

With this i am able to delete first five lines.same way i want to delete last five lines also.

Any suggestions ....

Thanks in advance.

Note : one more doubt why am i getting A.txt~.new,B.txt~.new even my *.sh,*.txt files are not opened? I have seen the same scenario in MS word when you open one Word document until you close that doc will get one temp XXX.doc~.tmp something.

Ignore my silly doubts

Cheers,
Ragavendran

team$ cat numbers
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
team$

team$ cat lines.sh
#!/usr/bin/ksh
echo "Enter No.of lines to remove from TOP : "
read top
echo "Enter No.of lines to remove from BOTTOM :"
read bottom

total=`wc -l < numbers`
endval=`expr $total - $bottom`
startval=`expr $top + 1`

echo "**** Showing lines $startval -- $endval **** \n"
sed -n ${startval},${endval}p $1
team$

team$ lines.sh numbers
Enter No.of lines to remove from TOP :
4
Enter No.of lines to remove from BOTTOM :
4
**** Showing lines 5 -- 11 ****

5
6
7
8
9
10
11
team$

put it in for loop to process all the files .