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extracting a field from directory path ??????

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# 1  
Old 07-09-2007
extracting a field from directory path ??????
Hi

I'll be getting a directory path as the input to the script.
E.g. 1 abc/fsg/sdfhgsa/fasgfsd/adfghad/XXX/fhsad
e.g. 2 sadfg/sadgjhgds/sd/dtuc/cghcx/dtyue/dfghsdd/XXX/qytq


This input will be stored in a variable.

My query is how to extract the field in a variable VAR which occurs just before XXX
Please note that XXX position is not fixed in the directory path.



Kindly provide the code.

Thanks and Best Regards
# 2  
Old 07-09-2007
Let me get this straight. You want the third last entry in the path, right ?
# 3  
Old 07-09-2007
Use awk (or similar tool) with / as a field separator and match the third pattern from the end.
# 4  
Old 07-09-2007
Re: VINO
No. i want the field just before XXX.



Quote:
Originally Posted by vino
Let me get this straight. You want the third last entry in the path, right ?
# 5  
Old 07-09-2007
Re: NEO
I want the field just before XXX wherever XXX is in the path. Position of XXX not fixed.

Quote:
Originally Posted by Neo
Use awk (or similar tool) with / as a field separator and match the third pattern from the end.
# 6  
Old 07-09-2007
Quote:
Originally Posted by skyineyes
I want the field just before XXX wherever XXX is in the path. Position of XXX not fixed.
Oh. So XXX is not a placeholder but an actual text.
# 7  
Old 07-09-2007
Is this a homework assignment?
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