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grep the line only if next line matches

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# 1  
Old 06-29-2007
grep the line only if next line matches
Hi

I have an Input of following sort

AAAA:
ProgName="PROGRAM"
BBBB:
ProgName="BBBBBB"
CCCC:
DDDD:
ProgName="PROGRAM"
SSSS:
ProgName="PROGRAM"
ZZZZ:
ProgName="PROGRAM"

I want to find the Lines which are followed by ProgName="PROGRAM"

Out Put
AAAA:
DDDD:
SSSS:
ZZZZ:
# 2  
Old 06-29-2007
Code:
awk '/ProgName="PROGRAM"/ { print prv_line; next } { prv_line = $0 }' inputfile

# 3  
Old 06-29-2007
Code:
sed -n "N;/\n.*PROGRAM/P;D" filename

# 4  
Old 06-29-2007
perl -ne 'print if /THIS/../THAT/'
# 5  
Old 06-29-2007
Thanks anbu aigles
# 6  
Old 07-10-2007
Hi
Im very new to this Smilie
i kinda have the same problem but I need lines followed by empty lines.
Input looks like this:

d:/bla1/bla/bla
d:/bla2/bla/bla

some text

d:/bla3/bla/bla
d:/bla4/bla/bla

I need the line d:/bla2/bla/bla

Can anyone help?

Thanks
# 7  
Old 07-10-2007
awk '/^$/ { print prv_line; next } { prv_line = $0 }' file_name
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