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Count the number of occurence of perticular word from file

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# 29  
Old 08-09-2007
Quote:
Originally Posted by Shell_Life
Reborg,
Using the same test data:
Code:
a aa aaa
aaa aa a
aaa aa a aaa aa a aaa

Using your solution to find the number of 'a' words:
Code:
awk 'BEGIN {RS="a" } END { print NR }' FILE

Gives total of '28' when the result is '4'.
Firstly the input data in this case is nonsensical, secondly the OP asked for the number of occurrences of a word in a file, not the number of occurrences where the word occurs only as a word, while I believe yours is the intended interpretation, without knowing the OPs intention, you cannot state for sure which is correct.
# 30  
Old 08-09-2007
For the other case:
Code:
awk 'BEGIN{RS ="(^|[[:punct:]]|[[:space:]])word([[:punct:]]|[[:space:]]|$)" } END { print NR }' file

# 31  
Old 08-10-2007
try this
count1=`wc -w inputfile`
count2=`sed s/word/" "/g inputfile |wc -w`

/*number of word =count1-count2*/
# 32  
Old 08-10-2007
try this
count1=`wc -w inputfile`
count2=`sed s/word/" "/g inputfile |wc -w`

/*number of word =count1-count2*/
# 33  
Old 08-10-2007
Quote:
Originally Posted by fazliturk
count1=`wc -w inputfile`
count2=`sed s/word/" "/g inputfile |wc -w`

/*number of word =count1-count2*/
I don't think this works if the word is in the middle of a larger word.
Code:
$echo compoundwordinmiddle >inputfile      
$count1=`wc -w inputfile`                  
$count2=`sed s/word/" "/g inputfile |wc -w`
$echo $count1
1 inputfile
$echo $count2
2

# 34  
Old 08-10-2007
MySQL
Here is the command which you can use-

grep -o "string" filename | wc -w
# 35  
Old 08-10-2007
Quote:
Originally Posted by rinku
I want to count the number of occurence of perticular word from one text file.

Please tell me "less" command is work in ksh or not. If it is not working then instead of that which command will work. Smilie
try this
count1=`wc -w inputfile`
count2=`sed s/word/" "/g inputfile |wc -w`

/*number of word =count1-count2*/
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