Count the number of occurence of perticular word from file


 
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# 15  
Old 08-08-2007
Quote:
Originally Posted by matrixmadhan
This is absolutely working as expected.

Input is
aa<space>
aa

only the pattern in second line "aa" matches and not the one in the first line.

Smilie
I'm not sure if your response is serious or joking. The OP was looking for a word count. Clearly there are 2 occurrances of aa, but the code counts one. Assuming you are serious, try

echo "aa\naa"

I get a blank line.
# 16  
Old 08-08-2007
This is a conceptual problem , check this:

Code:
$ printf "abc abc sasa abc\nabc sasa abc" |awk '
BEGIN {
RS=FS
print "<<<"FS"<<<<<"
}
{
print "<<<"$0"<<<<<"
if ( $0 ~ /abc/ )
   c++
}
END{
print c
}'

<<<abc<<<<<
<<<abc<<<<<
<<<sasa<<<<<
<<<abc
abc<<<<<
<<<sasa<<<<<
<<<abc<<<<<

As you see we changed the RS to FS (blank space) so the pattern can´t match record number 4 , it contains a carriage return.

Hope this help.

Regards.
# 17  
Old 08-08-2007
Quote:
Originally Posted by Klashxx
This is a conceptual problem
Thanks. From what I can see, Shell_Life has the only viable posted solution.

I need to add that I think Klashxx's first awk solution works too.

Last edited by kahuna; 08-08-2007 at 06:25 PM.. Reason: Add Klashxx's first awjk solution
# 18  
Old 08-08-2007
Quote:
Originally Posted by kahuna
I'm not sure if your response is serious or joking. The OP was looking for a word count. Clearly there are 2 occurrances of aa, but the code counts one. Assuming you are serious, try

echo "aa\naa"

I get a blank line.
What is the need for me to joke here ?

Words you have used really have taken me aback.

Ok. coming to the point with your example.

try this first and then the later solution

Code:
echo "aa\naa" | awk ' BEGIN {RS=FS} { print $0, length, NR } '

as per your argument the output should be something like

Code:
aa 2 1
aa 2 2

but the actual output is
Code:
aa<newline>
aa<newline>
 6 1

so the input string that is matched is "aa<newline>aa<newline>"

and not 'aa' and 'aa' individually

eventually awk will not match the above pattern with 'aa'
and hence there is no effective result.

Hope this clears !
# 19  
Old 08-08-2007
Quote:
Originally Posted by matrixmadhan
so the input string that is matched is "aa<newline>aa<newline>"
Thank you. I understand the issue. My point is that the code fails to solve the original problem. It does not count the number of occurrences of the given string. Your posting almost makes it sound like the code is right, so the original problem must be wrong.Smilie
# 20  
Old 08-08-2007
Quote:
Originally Posted by rinku
I want to count the number of occurence of perticular word from one text file.

Please tell me "less" command is work in ksh or not. If it is not working then instead of that which command will work. Smilie
See here for example
# 21  
Old 08-08-2007
sample.txt file:
Code:
This is line 1 abc and abc
This is line 2 abc

I'm trying to seperate the occurrences per line by inserting a newline character before and after the word. Once they are newline delimeted, i could grep them to get the total count. however i'm stuck, the \n character does not seem to work...
Code:
cat sample.txt | sed -e 's/\(abc\)/\n\1\n/g' | grep -c abc

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