Count the number of occurence of perticular word from file


 
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# 8  
Old 08-08-2007
Quote:
awk '
BEGIN {
RS=FS
}
{
if ( $0 ~ /abc/ )
c++
}
END{
print c++
}' lsample.txt
Here,

print statement should have been

Code:
print ++c

# 9  
Old 08-08-2007
Quote:
Originally Posted by Klashxx
Code:
awk '
BEGIN {
RS=FS
}
{
if ( $0 ~ /abc/ )
   c++
}
END{
print c++
}' lsample.txt

there is one more problem with that

with the input posted by Shell and for search pattern as "aa" it would match "aaa" also

try this,
Code:
awk ' BEGIN {RS=FS} { if ( $0 ~ /^aa$/ ) { c++; i=NR; } } END{if ( i == NR ) { c++ } print c}' filename

# 10  
Old 08-08-2007
Quote:
Originally Posted by matrixmadhan
Code:
awk ' BEGIN {RS=FS} { if ( $0 ~ /^aa$/ ) { c++; i=NR; } } END{if ( i == NR ) { c++ } print c}' filename

I'm not sure this is working
Code:
$echo "aa \naa" |awk ' BEGIN {RS=FS} { if ( $0 ~ /^aa$/ ) { c++; i=NR; } } END{if ( i == NR ) { c++ } print c}' 
1

# 11  
Old 08-08-2007
Quote:
Originally Posted by Klashxx
Use:
Code:
awk '{ 
     for (i=1;i<=NF;i++)
         if ( $i == "abc")
         c++
     }
END{
print c}' sample.txt

Or:
Code:
awk '
BEGIN {
RS=FS
}
{
if ( $0 ~ /abc/ )
   c++
}
END{
print c++
}' lsample.txt

typo here -->should be:
Code:
print c

Obviously, you have to delimit your pattern to get expected result.

Cheers.
# 12  
Old 08-08-2007
Quote:
Originally Posted by Klashxx
Obviously, you have to delimit your pattern to get expected result.
How would you delimit? I tried
Code:
$echo 'abc abc' |awk '
BEGIN {
RS=FS
}
{
if ( $0 ~ /^abc$/ )
   c++
}
END{
print c
}'
1

# 13  
Old 08-08-2007
Quote:
Originally Posted by kahuna
I'm not sure this is working
Code:
$echo "aa \naa" |awk ' BEGIN {RS=FS} { if ( $0 ~ /^aa$/ ) { c++; i=NR; } } END{if ( i == NR ) { c++ } print c}' 
1


This is absolutely working as expected.

Input is
aa<space>
aa

only the pattern in second line "aa" matches and not the one in the first line.

Smilie
# 14  
Old 08-08-2007
Quote:
typo here -->should be:
Code:

print c

Obviously, you have to delimit your pattern to get expected result.

Cheers.
Changing to print c doesn't help.

It should be changed to the below as I had posted earlier . Smilie

Code:
awk ' BEGIN {RS=FS} { if ( $0 ~ /^aa$/ ) { c++; i=NR; } } END{if ( i == NR ) { c++ } print c}' filename

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