How to find the jobs running in background and stop


 
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# 1  
Old 10-03-2006
Bug How to find the jobs running in background and stop

Hi All,

I have requirement. I am running a job every 30mins. before starting the process, i need to check the process, if the process is still running then i need not trigger the process again, if it is not running then trigger the process again. I am using cron to trigger the shell script. Can you please help by telling the exact command. I am new to shell scriptiing. Smilie

Regards & Thanks in advance.
Srinivas
# 2  
Old 10-03-2006
Let us take below exampls as a script (urs_script)

4 S srikanth 20075 20074 0 75 0 - 1066 - 15:27 pts/10 00:00:00 usr_script

------------------------------------
Code:
FIND=`ps -elf | grep "usr_script" | grep -v grep`
if [ $? -eq 0 ]
then
	echo "process found'
	echo $FIND
	FINDPROC=`awk {print $4}`  # it reads forth column to find process id
	kill -9 $FINDPROC  # kills process id of the usr_scirpts procsses
else
	echo "process no found"
	#start your scirpt here
fi

go through this example

if any problem pls let me know to give proper solution
# 3  
Old 10-24-2007
Hi Guys,
How can i find the is the process is running in back ground.

Actually
# 4  
Old 10-24-2007
hey krk,

before checking how to find a process whether it is running in background or not ???? can you check and let us know, how to check whether any process is runnning irrespective of bg or fg ????
# 5  
Old 10-24-2007
if a process is appending with & means its running in bg

like

script_1.sh &
echo $!

you will get the process id
# 6  
Old 01-28-2008
Quote:
Code:
FIND=`ps -elf | grep "usr_script" | grep -v grep`
if [ $? -eq 0 ]
then
	echo "process found"
	echo $FIND
	FINDPROC=`awk {print $4}`  # it reads forth column to find process id
	kill -9 $FINDPROC  # kills process id of the usr_scirpts procsses
else
	echo "process no found"
	#start your scirpt here
fi

This didn't work for me, can anyone see what needs to be changed? Here's my output:

process found
0 S userName 21426 1 0 40 20 ? 14409 ? 15:12:34 pts/2 0:06 rmiregistry 1199
awk: syntax error near line 1
awk: illegal statement near line 1



Thanks!!
# 7  
Old 01-28-2008
Code:
FINDPROC=`echo "${FIND}" | awk '{print $4}'`

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