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convert date format YYYYMMDD to MM/DD/YYYY

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# 1  
Old 06-08-2006
convert date format YYYYMMDD to MM/DD/YYYY
In my shell script i have a variable which stores date in the format of YYYYMMDD. Is there any way to format this value to MM/DD/YYYY.

Thanks.
# 2  
Old 06-08-2006
Code:
echo "YYYYMMDD" | awk '
BEGIN {OFS="/"}
{print substr($1,5,2), substr($1,7,2), substr($1,1,4)}'

Regards,
Tayyab
# 3  
Old 06-08-2006
Quote:
Originally Posted by nasirgondal
In my shell script i have a variable which stores date in the format of YYYYMMDD. Is there any way to format this value to MM/DD/YYYY.

Thanks.
You have broken a rule by duplicating your thread. The other one is here - https://www.unix.com/post-here-to-contact-site-administrators-and-moderators/28120-changing-format-date.html.

Using shell script.
Code:
#! /bin/ksh

format=YYYYMMDD

YEAR=${format%????}
DAY=${format#??????}
MON=${format#$YEAR}
MON=${MON%$DAY}
echo $MON/$DAY/$YEAR

Using sed.
Code:
echo "YYYYMMDD" | sed -n -e "s_\(....\)\(..\)\(..\)_\2/\3/\1_p"

# 4  
Old 06-08-2006
It worked!
Thank you.
# 5  
Old 06-13-2006
hi all....

Want some clarification ..

In the below scripts ...

echo "YYYYMMDD" | awk 'BEGIN {OFS="/"}{print substr($1,5,2), substr($1,7,2), substr($1,1,4)}'

What is OFS..Also how does the '/' is placed inbetween..

Thanks in advance,
Arun....
# 6  
Old 06-13-2006
OFS is Output Field Separator, I don't know the internal technicle details of awk though I can imagine that awk puts each print command in a stack like
Code:
print substr($1,5,2)
print substr($1,7,2)
print substr($1,1,4)

and then separates each output of print with an OFS if defined, default OFS is " " a whitespace. Hope it helps.

Regards,
Tayyab
Last edited by tayyabq8; 06-13-2006 at 11:54 AM..
# 7  
Old 08-07-2008
hi nasirgondal,

I also wanted such a script. It works fine but if the date is not exactly in YYYYMMDD format, lets say YYYYMDD or YYYYMMD format its not working. Is there any solution even for this. Appreciate your help

#! /bin/ksh

format=YYYYMMDD

YEAR=${format%????}
DAY=${format#??????}
MON=${format#$YEAR}
MON=${MON%$DAY}
echo $MON/$DAY/$YEAR
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