Get range out using sed or awk, only if given pattern match

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Get range out using sed or awk, only if given pattern match

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09-23-2017

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Get range out using sed or awk, only if given pattern match

Input:

Code:

START
OS:: UNIX
Release: xxx
Version: xxx
END
START
OS:: LINUX
Release: xxx
Version: xxx
END
START
OS:: Windows
Release: xxx
Version: xxx
END

Here i am trying to get all the information between START and END, only if i could match OS Type.

I can get all the data between the range START and END, however i dont know how to match the pattern

Using SED

Code:

sed -n '/START/,/END/p'

using AWK

Code:

awk '/START/,/END/'

Expected Output while searching for Linux:

Code:

START 
OS:: LINUX 
Release: xxx 
Version: xxx 
END

need help!!

Thanks in Advance

Moderator's Comments:

Mod Comment

Please use CODE tags as required by forum rules!

Last edited by RudiC; 09-23-2017 at 06:40 AM.. Reason: Added CODE tags.

Dharmaraja

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09-23-2017

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Hello Dharmaraja,

Welcome to forums, I hope you will enjoy learning/sharing knowledge here. Could you please try following and let me know if this helps you.

Code:

awk '/START/{count++} /OS.*LINUX/ && count{count++} /END/ && count==2{print val RS $0;val=count="";next}{val=val?val ORS $0:$0}/END/{count=val=""}'  Input_file

Output will be as follows.

Code:

START
OS:: LINUX
Release: xxx
Version: xxx
END

EDIT: Adding a non-one liner form of solution too now.

Code:

awk '
/START/{
  count++
}
/OS.*LINUX/ && count{
  count++
}
/END/ && count==2{
  print val RS $0;
  val=count="";
  next
}
{
  val=val?val ORS $0:$0
}
/END/{
  count=val=""
}
'   Input_file

Thanks,
R. Singh

RavinderSingh13

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09-23-2017

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Try also

Code:

awk -vRS="END\n" -vORS="END\n" '/[Ll][Ii][Nn][Uu][Xx]/' file
START
OS:: LINUX
Release: xxx
Version: xxx
END

RudiC

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09-23-2017

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You can try this one too

Code:

sed -n '/START/{N;/LINUX/{:A;N;/END/!bA;p;q}}' infile

ctac_

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