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awk to print the string between 3rd and 4th backslashs to end of line

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# 1  
Old 09-13-2017
awk to print the string between 3rd and 4th backslashs to end of line
im trying to get

awk to print the string between 3rd and 4th backslashs to end of line

test could be any word

this

Code:
http://example.com/test/ >

to this

Code:
http://example.com/test/ > test

also the other way round insert string at end of line between 3rd and 4th backslashs
thanks
# 2  
Old 09-13-2017
Any attempts / ideas / thoughts from your side?
# 3  
Old 09-13-2017
hi

i know how to print string to end of line like this

Code:
awk '{print $0"append_to_end"}' file > file1

but the string between 3rd and 4th backslashs is ramdom

thats where im stuck

would like to also do it the other way round


appreciate your help thanks
# 4  
Old 09-13-2017
Hello bob123,

Could you please try following and let me know if this helps you.
Code:
sed 's/\(.[^//]*\)\(\/\/\)\(.[^/]*\)\(\/\)\(.[^\/]*\)\(.*\)/\1\2\3\4\5\6 \5/'  Input_file

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
bob123
# 5  
Old 09-13-2017
hi RavinderSingh13,

yeah that works
many thanks

i did close the space between 6 and 5 as i already had a space


Code:
sed 's/\(.[^//]*\)\(\/\/\)\(.[^/]*\)\(\/\)\(.[^\/]*\)\(.*\)/\1\2\3\4\5\6\5/' file

would you know how to do it the other way round

insert the string at the end between 3rd and 4th backslashs
# 6  
Old 09-13-2017
Hello bob123,

Could you please try following and let me know if this helps you.
Code:
awk -F"/" '{print $0,$4}'   Input_file

Thanks,
R. Singh
# 7  
Old 09-13-2017
Quote:
Originally Posted by RavinderSingh13
Hello bob123,

Could you please try following and let me know if this helps you.
Code:
awk -F"/" '{print $0,$4}'   Input_file

Thanks,
R. Singh
hi RavinderSingh13

yeah that works the same as the sed one you posted
thanks

any way to do it the other way round
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