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How to remove contents from file which are under bracket?

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# 1  
Old 09-07-2017
How to remove contents from file which are under bracket?
hello Friend,

In hostgroup file, i have define lots of hostgroups. I need to remove few of them without manually editing file. Need script or syntax.
I want to search particular on hostgroup_members and delete hostgoup defination of it.

for example.
Code:
define hostgroup{
        hostgroup_name          test
        alias                   test server
       hostgroup_members       test-server
}
define hostgroup{
        hostgroup_name          prd
        alias                   Prd server
       hostgroup_members       prd-server
}
define hostgroup{
        hostgroup_name          acc
        alias                   acc server
       hostgroup_members      acc-server
}

for example: suppose i delete prd-server hostgroup_members then my output will be below.
Code:
define hostgroup{
        hostgroup_name          test
        alias                   test server
       hostgroup_members       test-server
}
define hostgroup{
        hostgroup_name          acc
        alias                   acc server
       hostgroup_members      acc-server
}



Moderator's Comments:
Mod Comment
Please wrap all code, files, input & output/errors in CODE tags.
It makes it easier to read and preserves multiple spaces for indenting or fixed width data.
Last edited by rbatte1; 09-07-2017 at 10:10 AM.. Reason: Added CODE tags
# 2  
Old 09-07-2017
Dear ghpradeep,

I have a few to questions pose in response first:-
  • Is this homework/assignment? There are specific forums for these.
  • What have you tried so far?
  • What output/errors do you get?
  • What OS and version are you using?
  • What are your preferred tools? (C, shell, perl, awk, etc.)
  • What logical process have you considered? (to help steer us to follow what you are trying to achieve)
Most importantly, What have you tried so far?

There are probably many ways to achieve most tasks, so giving us an idea of your style and thoughts will help us guide you to an answer most suitable to you so you can adjust it to suit your needs in future.


We're all here to learn and getting the relevant information will help us all.


Kind regards,
Robin
# 3  
Old 09-07-2017
Code:
awk '{$0=$0} ; $0 !~ del && NF {print $0 RS}' RS="}" del="prd-server" hostgroup

# 4  
Old 09-08-2017
Thanks rdrtx1, above command working fine.

one query here. suppose hostgroup_members are blank. noting is there. is it possible to delete it.
example:

Code:
define hostgroup{
        hostgroup_name          acc
        alias                   acc server
       hostgroup_members     
}

# 5  
Old 09-08-2017
How about
Code:
awk '{$0=$0} ; $0 !~ del && NF {print $0 RS}' RS="}" del="hostgroup_members *\n" file

This User Gave Thanks to RudiC For This Post:
ghpradeep
# 6  
Old 09-08-2017
More correct for a Nagios-style hostgroup.cfg is probably
Code:
awk '
  /\{/ {bl++} /\}/ {bl--}
  (bl==1 && $1=="define" && $2~/^hostgroup *\{/) {
    hostgroup=1
    hbuf=""
  }
  {
    if (hostgroup==1) {
      if ($1=="hostgroup_members") {
        nh=split($2,H,/,/)
        new2=sep=""
        for (i=1;i<=nh;i++) if (host!=H[i]) {
          new2=(new2 sep H[i]); sep=","
        }
        if (new2!=$2) { $2=new2 }
        if (new2=="") delblk=1
      }
      hbuf=(hbuf $0 ORS)
      if (bl==0) {
        if (delblk==1) {
          delblk=0
        } else {
          printf "%s", hbuf
        }
      }
    } else { print }
  }
' host=prd-server hostgroup.cfg

It won't stumble over a { } subsection, and it will delete the given host from a list
Code:
  hostgroup_members    host1,host2,host3

# 7  
Old 09-11-2017
Hello MadeInGermany,

thanks for code. I checked and its working while passing single hostgroups_members name
Can we use same for multiple hostgroups_members to remove by passing file which contain hostgroups_members name.
like putting above code inside for for.
anything need to change in code?
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