Shell Programming and Scripting

Hi,

I currently have many log files for different webpages inside the folder /log/. The program allows the user to enter a month and then the grep function searches for it, the command i used is below:

grep -c "$month" ./log/*.log

This works and i can ascertain the number of matches, but I cannot find out how to format the name of the .log and the number of matches into two seperate columns. Kind of like:

Log Name Matches
--------------- --------

soccerscore.log 40
soccerfaqs 20

Any ideas how to do this?

At the moment its like

./logs/soccerscore.log:40

-Thanks for any help

Use sed for this.

Code:

grep -c "$month" ./log/*.log | sed 's/\.\/log\///g' | | sed 's/:/ /g'

or awk

Code:

grep -c "$month" | awk -F: {print $1,"   ",$1}'

It just does the same output as it does before when I use this.

The other awk one doesnt display the hits, it just displays the directory of the wepages in two columns.

Code:

grep -c "$month" ./log/*.log | { read a; echo ${a##*/} ; } | sed -e "s_\(.*\):\(.*\)_\1 \2_g"

Code:

 grep -c "$month" ./log/*.log | sed 's/\.\/log\///g' |  sed 's/:/ /g'

This very much works for me..
All that command does is to remove the "./log/" from the listing and replace ":" with " "

Ah, sorry I must have missed a bit of the code, was doing it early in the morning ¬_¬.

Is there anyway to format that so the webpages are in one colum and the seperated hits in another?

Thanks for the help btw