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# 1  
Old 07-27-2017
Shell Script for formatted output
Code:
06/26/2017 23:40:40       CAUAJM_I_10082 [aspsun14 connected for IOALPPRXXBD_ALPGLGENFAALL 55443.15215291.1]
 06/26/2017 23:40:40       CAUAJM_I_40245 EVENT: CHANGE_STATUS    STATUS: STARTING        JOB: IOALPPRXXBD_ALPGLGENFAALL MACHINE: aspsun14
 06/26/2017 23:40:42       CAUAJM_I_40245 EVENT: CHANGE_STATUS    STATUS: RUNNING         JOB: IOALPPRXXBD_ALPGLGENFAALL MACHINE: aspsun14
 06/26/2017 23:49:19       CAUAJM_I_40245 EVENT: CHANGE_STATUS    STATUS: SUCCESS         JOB: IOALPPRXXBD_ALPGLGENFAALL MACHINE: aspsun14        EXITCODE:  0
 06/27/2017 23:40:23       CAUAJM_I_40245 EVENT: CHANGE_STATUS    STATUS: STARTING        JOB: IOALPPRXXBD_ALPGLGENFAALL MACHINE: aspsun14
 06/27/2017 23:40:24       CAUAJM_I_10082 [aspsun14 connected for IOALPPRXXBD_ALPGLGENFAALL 55443.15236942.1]
 06/27/2017 23:40:25       CAUAJM_I_40245 EVENT: CHANGE_STATUS    STATUS: RUNNING         JOB: IOALPPRXXBD_ALPGLGENFAALL MACHINE: aspsun14
 06/27/2017 23:48:19       CAUAJM_I_40245 EVENT: CHANGE_STATUS    STATUS: SUCCESS         JOB: IOALPPRXXBD_ALPGLGENFAALL MACHINE: aspsun14        EXITCODE:  0
 06/28/2017 23:41:36       CAUAJM_I_40245 EVENT: CHANGE_STATUS    STATUS: STARTING        JOB: IOALPPRXXBD_ALPGLGENFAALL MACHINE: aspsun14
 06/28/2017 23:41:37       CAUAJM_I_10082 [aspsun14 connected for IOALPPRXXBD_ALPGLGENFAALL 55443.15258301.1]
 06/28/2017 23:41:38       CAUAJM_I_40245 EVENT: CHANGE_STATUS    STATUS: RUNNING         JOB: IOALPPRXXBD_ALPGLGENFAALL MACHINE: aspsun14
 06/28/2017 23:48:47       CAUAJM_I_40245 EVENT: CHANGE_STATUS    STATUS: SUCCESS         JOB: IOALPPRXXBD_ALPGLGENFAALL MACHINE: aspsun14        EXITCODE:  0

I have a file having above content, I want the output like, job name then start time then End time
Code:
IOALPPRXXBD_ALPGLGENFAALL 06/26/2017 23:40:40 06/26/2017 23:49:19
IOALPPRXXBD_ALPGLGENFAALL 06/27/2017 23:40:23 06/27/2017 23:48:19
IOALPPRXXBD_ALPGLGENFAALL 06/28/2017 23:41:36 06/28/2017 23:48:47

could somebody help me with a shell script for this requirement. I am using ksh in AIX environment

Moderator's Comments:
Mod Comment Please use code tags for data examples
Last edited by jim mcnamara; 07-27-2017 at 09:13 AM..
# 2  
Old 07-27-2017
Good, well formed question for a first effort.

What have you tried so far?
Can you show us where you are stuck? The point of the forums is to help you learn, not to write code for you.
These 2 Users Gave Thanks to jim mcnamara For This Post:
rbatte1 Sandeep Behera
# 3  
Old 07-28-2017
Quote:
Originally Posted by jim mcnamara
Good, well formed question for a first effort.

What have you tried so far?
Can you show us where you are stuck? The point of the forums is to help you learn, not to write code for you.

Code:
#!bin/ksh

job_name=$1
echo $job_name

ls /Autosys/CA/UnicenterAutoSysJM/autouser.ACE/out/event_demon.ACE* | sort -r | awk -F "/" '{print $7}' > logfile.txt

path="/Autosys/CA/UnicenterAutoSysJM/autouser.ACE/out"


 while read line;

 do

                            zgrep $job_name $path/$line  | sed -e 's/\[/ /' -e 's/\]/ /'  >> feoj.txt



  done < logfile.txt

cat feoj.txt | sort -k1 | awk '/START|SUCCESS/ { print $1,$2}'

Thanks for the reply. I have tried this but the out put is in one column, please give me some hint so that I can try.


Moderator's Comments:
Mod Comment
Please wrap all code, files, input & output/errors in CODE tags.
It makes it easier to read and preserves multiple spaces for indenting or fixed-witch data.
Last edited by rbatte1; 07-28-2017 at 08:26 AM.. Reason: Code tags
# 4  
Old 07-28-2017
A few pointers to tidy up first:-
  • Please wrap CODE tags [CODE] & [/CODE] around code, files, input & output/errors.
  • The append to feoj.txt can be added to the end of the loop
  • There is no need to use cat to pipe the file, just name the file as part of the command
  • Putting the awk before the sort will mean sort has less processing to do.
  • If you don't need to store the file, you can avoid the IO altogether.
  • What are the full filenames for the log files? The logfiles should be in order if they have a correct timestamp in the name.
    If they are just aged my moving them through the suffixes of -1, -2, -3 etc., then we can adjust for that.

Doing just these (but not removing the final sort) gives me this:-
Code:
#!bin/ksh

job_name=$1
echo $job_name

path="/Autosys/CA/UnicenterAutoSysJM/autouser.ACE/out"

cd $path                        # ..... or 'pushd $path' if you prefer so you can 'popd' later if needed

for filename in event_demon.ACE*
do
   zgrep $job_name $filename  | sed -e 's/\[/ /' -e 's/\]/ /'
done  | awk '/START|SUCCESS/ { print $1,$2}' | sort -k1


Now that it's a bit neater, where is it going wrong?


Kind regards,
Robin
Last edited by rbatte1; 07-28-2017 at 09:22 AM..
This User Gave Thanks to rbatte1 For This Post:
Sandeep Behera
# 5  
Old 07-28-2017
I am quite enthused you left something over for me, dear colleague ;-)

Quote:
Originally Posted by rbatte1
Code:
#!bin/ksh

should of course be:

Code:
#! /bin/ksh

I hope this helps.

bakunin
These 2 Users Gave Thanks to bakunin For This Post:
rbatte1 Sandeep Behera
# 6  
Old 07-28-2017
yes it works, but my concern with the output format.

How can I display the value of variable side by side like below :


Code:
Job Name                                  Start Time                 End Time
IOALPPRXXBD_ALPGLGENFAALL 06/26/2017 23:40:40 06/26/2017 23:49:19
IOALPPRXXBD_ALPGLGENFAALL 06/27/2017 23:40:23 06/27/2017 23:48:19
IOALPPRXXBD_ALPGLGENFAALL 06/28/2017 23:41:36 06/28/2017 23:48:47

Last edited by rbatte1; 07-28-2017 at 09:17 AM.. Reason: Code tags again. Warning issued.
# 7  
Old 07-28-2017
Can you show us (wrapped in CODE tags please) what you get so far. We can then think about how to progress. Otherwise we're a bit blind.

What do you want to happen if there is not a closing SUCCESS record in the log file?



Regards,
Robin
Last edited by rbatte1; 07-28-2017 at 09:25 AM.. Reason: Question about failed or incomplete messages
This User Gave Thanks to rbatte1 For This Post:
Sandeep Behera
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