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sed command on AIX, replace specific characters

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# 8  
Old 03-31-2017
Quote:
Originally Posted by MadeInGermany
I missed something: \1 is certainly a backreference to the ( ) and should become $1 in perl, and needs to be separated from the following text
Code:
perl -i.Original -pe '/^4000/ and s/(.{136}) 36|000/${1}036/' file

saved me thereSmilieSmilie
# 9  
Old 03-31-2017
Quote:
Originally Posted by MadeInGermany
I missed something: \1 is certainly a backreference to the ( ) and should become $1 in perl, and needs to be separated from the following text
Code:
perl -i.Original -pe '/^4000/ and s/(.{136}) 36|000/${1}036/' file

AFAIK in perl both $1 and \1 can be used for backreference:

Quote:
Absolute numbered groups were referred to using \1 , \2 , etc., and this notation is still accepted (and likely always will be). But it leads to some ambiguities if there are more than 9 capture groups, as \10 could mean either the tenth capture group, or the character whose ordinal in octal is 010 (a backspace in ASCII). Perl resolves this ambiguity by interpreting \10 as a backreference only if at least 10 left parentheses have opened before it. Likewise \11 is a backreference only if at least 11 left parentheses have opened before it. And so on. \1 through \9 are always interpreted as backreferences.
perlre - perldoc.perl.org
# 10  
Old 04-03-2017
@scrutinizer thanks for tip Smilie
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