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How to split string in someinteresting cases?

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# 1  
Old 03-03-2017
How to split string in someinteresting cases?
I have a variable
Code:
var=safe_alloc_TBA_details_TXXXXXX_YYYYMMDDhhmmss.csv

I want to get a part safe_alloc_TBA_details_T
If I do :
Code:
PR=`echo "$var" | awk -F'_' '{for (i=1; i<NF; i++) printf("%s_", $i)}'`

Then echo "$PR = safe_alloc_TBA_details_"
How can I cut the string so that get it safe_alloc_TBA_details_T?


Moderator's Comments:
Mod Comment Please use CODE tags as required by forum rules!
Last edited by RudiC; 03-03-2017 at 01:29 PM.. Reason: Added CODE tags.
# 2  
Old 03-03-2017
Like so?
Code:
echo ${var%${var#*_*_*_*_?}}
safe_alloc_TBA_details_T

# 3  
Old 03-03-2017
RudiC,
I don't know amount of delimiters. It can be 4, 5 7, may be 2. I need some generic regular expression

Thanks
# 4  
Old 03-03-2017
Quote:
Originally Posted by digioleg54
RudiC,
I don't know amount of delimiters. It can be 4, 5 7, may be 2. I need some generic regular expression

Thanks
what can be assumed constant in this pattern/string?
Code:
safe_alloc_TBA_details_TXXXXXX_YYYYMMDDhhmmss.csv

will this help?
Code:
echo 'safe_alloc_TBA_details_TXXXXXX_YYYYMMDDhhmmss.csv' | sed 's/\(.*_T\)[^_][^_]*_.*csv$/\1/'

Last edited by vgersh99; 03-03-2017 at 03:25 PM..
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