Capture the last record number using "awk" NR variable


 
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# 8  
Old 02-08-2017
Expanding a bit on what Corona688 said, and commenting on your own proposal in post#4: See what happens if your (syntactically corrected) code (action "print" assumed) works on a file like
Code:
cat file
0 1 2 3 4 5 6 7 8 9 A B C D E F
0 1 2 3 4 5 6 7 8 9 A B C D E F
0 1 2 3 4 5 6 7 8 9 A B C D E F
0 1 2 3 4 5 6 7 8 9 A B C D E F
0 1 2 3 4 5 6 7 8 9 A B C D E F
0 1 2 3 4 5 6 7 8 9 A B C D E F
0 1 2 3 4 5 6 7 8 9 A B C D E F
0 1 2 3 4 5 6 7 8 9 A B C D E F
awk '{for(i=1;i<=NR;i++) printf "%s ", $i; printf RS}' file
0 
0 1 
0 1 2 
0 1 2 3 
0 1 2 3 4 
0 1 2 3 4 5 
0 1 2 3 4 5 6 
0 1 2 3 4 5 6 7


Last edited by RudiC; 02-09-2017 at 03:21 AM..
# 9  
Old 02-08-2017
In awk one normally loops over the fields. NF is the number of fields.
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