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Print remaining lines using grep

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# 8  
Old 12-09-2016
Yeah got the sorted, thanks guys is there a way to add multiple pattern search of string

Code:
ERROR - Not a valid
ID : 123


ERROR - Not a valid
hello
+ echo ID : 124

SUCCESS - Valid
ID : 12

WARNING

IGNORE ERROR

Desired output
Code:
There is Error for ID 123

There is Error for ID 12

WARNING

Tried below
awk '($0 ~ /ERROR|WARNING/){Q=$0;next} ($1 ~ /ID/){print Q ORS "There is Error for ID " $NF}' test.txt

i need to exlcude IGNORE ERROR
# 9  
Old 12-09-2016
Code:
awk '($0 ~ /ERROR/ && $0!~/IGNORE/){Q=$0;next} ($0 ~ /ID/){print Q ORS "There is Error for ID " $NF}' test.txt

This User Gave Thanks to itkamaraj For This Post:
rohit_shinez
# 10  
Old 12-09-2016
Perfect thanks guys
# 11  
Old 12-09-2016
Hello rohit_shinez,

Could you please try following and let me know if this helps you.
Code:
awk '($0 ~ /ERROR|WARNING/){Q=$0;next} ($1 ~ /ID/ && Q){print "There is Error for ID " $NF;Q=""}'    Input_file

Also as per your output shown, it will make sure first string ERROR should be there before any ID is coming then only it will print the ID. If you have any further requirements then kindly mention them too.

Thanks,
R. Singh
Last edited by RavinderSingh13; 12-09-2016 at 01:55 AM..
This User Gave Thanks to RavinderSingh13 For This Post:
rohit_shinez
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