Shell Programming and Scripting

i would like to do this in awk. but when i run this command, i get this:

Code:

awk: warning: escape sequence `\?' treated as plain `?'

i intend to use this on Linux Ubuntu, RedHat and AIX systems, so it needs to be portable.

an example of what im trying to do can be summed up this way:

Code:

PHPFILE='#!/usr/bin/php
<?php 
  phpinfo();
  hlight_file(__FILE__);
?>'

CHECK=$(printf "%s\n" "${PHPFILE}" | egrep "phpinfo|hlight_file")

if [ -z "${CHECK}" ] ; then
  printf "%s\n" "${PHPFILE}"
fi

as you can see here, i can accomplish what I want with the above. but, i want it to be shortened through awk so im not making any unnecessary external calls to system tools.

Try [?]>\n.

this fixed it. thank you!

Hi

Code:

sed -re '/^<\?php/,/\?>/{N;N;N;/.*phpinfo.*\n.*hlight_file.*\n?>/d}'  file

I don't know this type of sed, never studied, Can you please provide any tutorial/link to learn on this.