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awk and greping between lines

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# 1  
Old 09-25-2016
awk and greping between lines
i want to grab lines from a file that are between two patterns (including the lines that contain the pattern).

here's what im currently doing:

data.txt
Code:
aaa
bbb
cccc
ddd
eee
ffff
ddd

code:
Code:
awk '/bbb/,/fff/ && $0 !~ /ddd/' cdsnmp.sh

I want to grab lines between and including bbb and ffff, but i want to avoid the lines containing ddd
# 2  
Old 09-25-2016
Hello SkySmart,

Could you please try following and let me know if this helps you.
Code:
awk '($0 ~ /ddd/){next} ($0 ~ /bbb/){A=1} {if(A){print}} ($0 ~ /ffff/){A=0}'  Input_file

Output will be as follows.
Code:
bbb
cccc
eee
ffff

Thanks,
R. Singh
These 2 Users Gave Thanks to RavinderSingh13 For This Post:
rbatte1 SkySmart
# 3  
Old 09-25-2016
Try (which I think is simplest / the most straight forward):
Code:
awk '/bbb/,/fff/{if(!/ddd/) print}' file

or otherwise:
Code:
awk '/bbb/{p=1} p && !/ddd/; /fff/{p=0}' file


----
@ravindersingh: your approach could be further reduced to:
Code:
awk '/ddd/{next} /bbb/{A=1}A; /ffff/{A=0}' file

These 2 Users Gave Thanks to Scrutinizer For This Post:
rbatte1 SkySmart
# 4  
Old 09-25-2016
In sed:
Code:
 sed -ne '/ddd/d;/bbb/,/fff/p' file

This User Gave Thanks to greet_sed For This Post:
SkySmart
# 5  
Old 09-27-2016
Hi.

Also:
Code:
perl -wn -e 'if ( /bbb/../fff/ ) { print unless /ddd/ } ;' input-file

producing:
Code:
bbb
cccc
eee
ffff

On a system:
Code:
OS, ker|rel, machine: Linux, 3.16.0-4-amd64, x86_64
Distribution        : Debian 8.4 (jessie) 
perl 5.20.2

Best wishes ... cheers, drl
# 6  
Old 09-27-2016
The shortest awk resolution:

Code:
$ awk '/ddd/{next}/aaa/,/fff/' data.txt
aaa
bbb
cccc
eee
ffff

This User Gave Thanks to blastit.fr For This Post:
SkySmart
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