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Calculate percentage difference between two columns

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# 1  
Old 07-23-2016
Calculate percentage difference between two columns
I have a input text file in this format:

ITEM1 10.9 20.1
ITEM2 11.6 12
ITEM3 14 15.7
ITEM5 20 50.6
ITEM6 25 23.6

I want to print those lines which have more than 5% difference [negative or positive] between second and third columns.
# 2  
Old 07-23-2016
Hello ctrld,

Could you please try following and let me know if this helps you.
Code:
awk '{if((Q=100-(($2 * 100)/$3)) > 5 || Q <= -5){print Q, $0}}'  Input_file

Thanks,
R. Singh
Last edited by RavinderSingh13; 07-23-2016 at 03:00 PM..
This User Gave Thanks to RavinderSingh13 For This Post:
ctrld
# 3  
Old 07-23-2016
Appreciate your quick help. I got following output:
Code:
awk '{if((Q=100-(($2 * 100)/$3)) > 5 || Q >= -5){print Q, $0}}' input.txt
45.7711 ITEM1 10.9 20.1
3.33333 ITEM2 11.6 12
10.828 ITEM3 14 15.7
60.4743 ITEM5 20 50.6

Seems like a small tweak may be required to eliminate ITEM2 .
# 4  
Old 07-23-2016
Quote:
Originally Posted by ctrld
Appreciate your quick help. I got following output:
Code:
awk '{if((Q=100-(($2 * 100)/$3)) > 5 || Q >= -5){print Q, $0}}' input.txt
45.7711 ITEM1 10.9 20.1
3.33333 ITEM2 11.6 12
10.828 ITEM3 14 15.7
60.4743 ITEM5 20 50.6

Seems like a small tweak may be required to eliminate ITEM2 .
Hello ctrld,

As you had mentioned to take 5% in positve and negative both ways so I had kept it, could you please try following and let me know then if this helps you.
Code:
awk '{if((Q=100-(($2 * 100)/$3)) > 5){print Q, $0}}'  Input_file

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
ctrld
# 5  
Old 07-23-2016
This one works perfect.

Code:
awk '{if((Q=100-(($2 * 100)/$3)) > 5){print Q, $0}}' input.txt
45.7711 ITEM1 10.9 20.1
10.828 ITEM3 14 15.7
60.4743 ITEM5 20 50.6

Seems like awk is not considering if its negative or positive difference.
# 6  
Old 07-23-2016
This one works perfect.

Code:
awk '{if((Q=100-(($2 * 100)/$3)) > 5){print Q, $0}}' input.txt
45.7711 ITEM1 10.9 20.1
10.828 ITEM3 14 15.7
60.4743 ITEM5 20 50.6

Seems like awk is not considering if its negative or positive difference.
Thanks a lot for your quick assistance in this query.
# 7  
Old 07-23-2016
Quote:
Originally Posted by ctrld
This one works perfect.

Code:
awk '{if((Q=100-(($2 * 100)/$3)) > 5){print Q, $0}}' input.txt
45.7711 ITEM1 10.9 20.1
10.828 ITEM3 14 15.7
60.4743 ITEM5 20 50.6

Seems like awk is not considering if its negative or positive difference.
Hello ctrld,

No, awk considers the difference between +5 and -5, offcourse if you will not put and +ve or -ve sign with any digit as per basic mathematics it will considered as a positive number, you could put -5 there and could see it will calculate from there.

Thanks,
R. Singh
This User Gave Thanks to RavinderSingh13 For This Post:
ctrld
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