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awk regexp to print repetitive pattern

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Top Forums Shell Programming and Scripting awk regexp to print repetitive pattern
# 8  
Old 07-15-2016
I'm a little confused since the code you showed us is printing tabs between the hyphens in the output, but the sample output you provided from that command has four spaces at those spots instead of a singe tab. And, the output you showed us should have output lines in the order of the lines in file1, but it doesn't. It also seems strange that there are three trailing spaces on each line in your sample file2, but there are zero, two, or three spaces on the corresponding lines in your sample output. I don't know if that matters for the output you hope to produce, but it makes it hard to guess at what you are really trying to do???

So, with lots of unsupported guesswork, the following (combining earlier suggestions with your code to merge files and making the wild assumption that if you want tabs between hyphens, you might also want tab to be your output field separator) might or might not come close to producing the output you want:
Code:
awk '
NR==FNR {
	A[$2] = $0
	if(FNR == 1) {
		NFA = NF
		$0 = ""
		OFS = "-\t"
		$NFA = "-"
		dashes = $0
		OFS = "\t"
	}
	next
}
{	print $0, (($1 in A) ? A[$1] : dashes)
}' file2 file1

As always, if you want to try this on a Solaris/SunOS system, change awk to /usr/xpg4/bin/awk or nawk.
This User Gave Thanks to Don Cragun For This Post:
yifangt
# 9  
Old 07-16-2016
Quote:
Originally Posted by yifangt
Can I say there is no regexp for this case in awk, similar to your perl script ?perl -e '{print "-\t"x11, "-\n"}'
Thanks a lot!
You seem to be caught in an error: regexes exist for searching/matching purposes ONLY. You can't print them. For printing a repetitive pattern, you need to type it as is, use a loop, or fall back to tricks as posted before.
This User Gave Thanks to RudiC For This Post:
yifangt
# 10  
Old 07-17-2016
Adding a varying number of fields to an incomplete line might be achieved like
Code:
awk '
NR == FNR       {A[$2] = $0
                  next
                }
!A[$1]          {A[$1] = sprintf ("%*s", 14-NF, "-")
                 gsub (/ /, "-\t", A[$1])
                }
                {print $0, A[$1]
                }
' file2 file1 
TCONS_00000001    W5GKA3_WHEAT XLOC_000001 TCONS_00000001 LOC_Os02g39790.2 47.273 55 24 2 3855 4016 335 385 3.60e-04  
TCONS_00000002    W5GKA3_WHEAT XLOC_000001 TCONS_00000002 LOC_Os02g39790.2 47.273 55 24 2 2368 2529 335 385 2.35e-04  
TCONS_00000011    I1IBH3_BRADI XLOC_000001 TCONS_00000011 LOC_Os02g39790.2 47.273 55 24 2 2200 2361 335 385 2.28e-04   
TCONS_00000009    W5GKA3_WHEAT XLOC_000001 TCONS_00000009 LOC_Os02g39790.2 47.273 55 24 2 5083 5244 335 385 2.83e-04  
TCONS_00000005    I1IBH3_BRADI -	-	-	-	-	-	-	-	-	-	-	-
TCONS_00000006    I1IBH3_BRADI -	-	-	-	-	-	-	-	-	-	-	-
TCONS_00000007    W5GKA3_WHEAT XLOC_000001 TCONS_00000007 LOC_Os02g39790.2 47.273 55 24 2 3553 3714 335 385 3.09e-04


EDIT: Or just use a for loop...




.
Last edited by RudiC; 07-17-2016 at 07:18 AM..
This User Gave Thanks to RudiC For This Post:
yifangt
# 11  
Old 07-18-2016
It started to deviate from my original question, and before it goes too far, I accept the answer by RudiC
Quote:
Can I say there is no regexp for this case in awk, similar to your perl script ?
Code:
perl -e '{print "-\t"x11, "-\n"}'

You seem to be caught in an error: regexes exist for searching/matching purposes ONLY. You can't print them. For printing a repetitive pattern, you need to type it as is, use a loop, or fall back to tricks as posted before.
Thanks again for all your replies.
Last edited by yifangt; 07-18-2016 at 01:21 PM..
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