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To learn last login date

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# 1  
Old 11-22-2015
To learn last login date
Hello,

HTML Code:
[root@server ~]# last| grep -v "root" | head -1
evam     pts/4        10.16.241.217    Fri Nov 20 10:48    gone - no logout
I can see last date without year. But I want to learn year of the last login.

HTML Code:
[root@server ~]# last| grep -v "root" | head -1 | awk '{print$4" "$5" "$6" "$7 }'
Fri Nov 20 10:48
How can I understand year of last login?

Best regards,
Moderator's Comments:
Mod Comment Please use CODE tags (not ICODE tags) when displaying full-line and multi-line sample input, sample output, and code segments.
Last edited by getrue; 11-23-2015 at 02:47 AM.. Reason: Change ICODE tags to CODE tags.
# 2  
Old 11-22-2015
Please, try last -F
# 3  
Old 11-23-2015
thanks dud.

#last -F working on Linux but it doesn't work on Solaris, HP-UX and IBM-AIX

HTML Code:
# last -F| grep -v "root" | head -1 | awk '{print$4" "$5" "$6" "$7" "$8}'
Thu Nov 19 11:27:54 2015
Is there any alternative solution?
# 4  
Old 11-23-2015
*nix timestamps are printed with time but without year if occurred within the last 6 months. Beyond that, year replaces the time.
# 5  
Old 11-23-2015
SysV Unix does not store the year in wtmp.
Most if not all Unix vendors have migrated to own extended wtmp files, named wtmpx or wtmps.
When adapting the last command, some vendors added new non-standard options.
Here is a portable script that makes some guesses and tries to compute the missing year:
Code:
last | PATH=/usr/xpg4/bin:/bin:/usr/bin awk '
BEGIN {
m["Jan"]=1
m["Feb"]=2
m["Mar"]=3
m["Apr"]=4
m["May"]=5
m["Jun"]=6
m["Jul"]=7
m["Aug"]=8
m["Sep"]=9
m["Oct"]=10
m["Nov"]=11
m["Dec"]=12
}
{
for (i=4;i<NF;i++) {
  if (($(i-1) in m) && $i~/^[0-9]?[0-9]$/ && $(i+1)~/^[0-9]/) {
    if ((m[$(i-1)]>pm || m[$(i-1)]==pm && $i>pday) && NR>1) year--
    pm=m[$(i-1)]; pday=$i
    $i=$i " " year
    break
  }
}
print
}' year=`date +%Y`

This User Gave Thanks to MadeInGermany For This Post:
getrue
# 6  
Old 11-23-2015
Solaris:

Code:
lastlog

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