Shell Programming and Scripting

Dear Sir,

I need to remove the word /klp/ in all the files present in the directories

can you tell me how to remove the word globally.

Code:

grep "/klp/" * -exec ls -l

Once the above command is exectubed I could see lot of files displayed.

This has a few issues already.
I would use find to generate the list to work with and then for each file you find, you could use grep, sed or perhaps awk to make the edit depending how you want the edit to affect the file.

I would suggest initially that you should use this to select the files to work on:-

Code:

find $dir -type f -exec grep -l "/klp/" {} /dev/null \;

I would avoid running the ls -l as you will only have to extract the file again information later on.

The use of /dev/null causes grep to output the filename and when combined with the -l flag does not show you the actual matching lines.

From this list, you can then decide what to do next. Do you want to:-Can you elaborate?


Thanks, in advance,
Robin

thanks for your detailed explanation.

I would need to delete that particular word in all the files present in the one particual directories.

The particular word

Code:

 /klp/

is present in the directory

Code:

 /us/hub/

my request is to delete the particular matched string alone.

So if your input file contains the records:-

Code:

abc/def/hij/klp/001
zyx/wvu/tsr/klm/002

.... does that mean you output should be:-
I just want to be sure that I am/we are working on the right idea.



Robin

Code:

 string ="/klp//"

everything is perfect. from your example only the

Code:

 / /

slash also need to be removed.

only the particular string need to be deleted in all the files.

Can do this using for loop in directory

Code:

for file in `ls *files.txt`
do
newfile=$file"_new"
cat $file | sed 's/klp//g' >$newfile
done

To ramkumar15,

Which option is it then? Leaving blanks or not?


To kidSandy,

There is again the issue over the number of files that your command will be expanded to.



Robin