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Assigning * as value in a ksh array

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# 1  
Old 02-27-2015
Assigning * as value in a ksh array
I want to extract each and single character from a password string and put it in an array.

I tried this :
Code:
set -A password "echo $passwd | awk '{for (i=1; i<=length($1); i++) printf "%s ",substr($1,i,1)}'`

It's working as long that the password string doesn't contains any *

I tried a few thing but no luck. Anyone having an idea ?
# 2  
Old 02-27-2015
There is no need to set it in an array. You can use the substring operator to get each individual character. It works like ${variablename:offset:length} so use 1 for length and give it a value of 0 through length for offset.

This also avoids needing to split on spaces, which allows people to put spaces, wildcards, and other special characters in their passwords without this choking.

Code:
N=2
pass="12345"
echo "${pass:$N:1}"

# 3  
Old 02-27-2015
Thanks for your quick response but its not working on my system. I'm on AIX 7.1

Code:
ce9888@a03d:/users/ce9888 > N=2
ce9888@a03d:/users/ce9888 > pass="12345"
ce9888@a03d:/users/ce9888 > echo "${pass:$N:1}"
ksh: "${pass:$N:1}": 0403-011 The specified substitution is not valid for this command.
ce9888@a03d:/users/ce9888 >

# 4  
Old 02-27-2015
You must be using ksh88, which is 27 years old and counting. This isn't going to be pretty.

Try
Code:
N=1
set -a pass
while [ "$N" -le "${#password}" ]
do
        pass[$N]="`echo \"$password\" | cut -b $N`"
        let N=N+1
done

# 5  
Old 02-28-2015
Quote:
Originally Posted by ce9888
Thanks for your quick response but its not working on my system. I'm on AIX 7.1
Quote:
Originally Posted by Corona688
You must be using ksh88, which is 27 years old and counting.
In AIX (every AIX since 3.2 - the one i started with at the beginning of the nineties) the default login shell is a ksh88 version f. Fortunately there is a ksh93 installed per default (in every AIX since 4.something, ~2000), you just have to start it:

Code:
/usr/bin/ksh93

contains a ksh93 version t on AIX.

@Corona:

even ksh88 understands POSIX process substitution ("$(....)")and can do variable manipulation:

Code:
x="ab*de"

while [ -n "$x" ] ; do
     first="${x%${x#?}}"
     x="${x#?}"
     print - "First: $first \tRest of x: $x"
done

I hope this helps.

bakunin
Last edited by bakunin; 02-28-2015 at 10:45 AM..
This User Gave Thanks to bakunin For This Post:
Corona688
# 6  
Old 03-02-2015
That's a neat trick to get the first character without using substrings in a crummy shell. I'll remember that.
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