If with grep in awk


 
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Old 09-18-2014
Quote:
Originally Posted by stew
Thanks ShamRock

My doubt is if I pass only server name in output file 0
Code:
BEGIN {while (getline l < "servers name input file" > 0)

Its has only server (aaaa,bbbb,cccc...) then I can compare server name with server-version
Code:
aaaa="server-version

i.e,  if ($0 ~ "server-version" && $0 ~ "disk space")        print $0 > "output1.txt"

It has been a long time since I seen a thread that confused me as much as this thread.

Sometimes you have a list of servers; sometimes you have a file that contains a list of servers; sometimes the servers can just to be extracted from the data as the contents of the 1st line in an empty line separated group of lines.

Sometimes you are looking for lines that have server names like aaaa, bbbb, cccc, etc.; other times you have server names like aaaa.com, bbbb.com, cccc.com, etc. And, now you are looking for server name "server-version"???

Sometimes you're looking for lines that contain "server version"; other times you're looking for lines that contain "server-version".

Sometimes you're looking for lines that contain "diskspace"; other times you're looking for lines that contain "disk space".

Every time someone gives you some code to try, you say it doesn't work and show us new sample data that contains different strings to match.

Sometimes you want data in a file that contains complete groups in three files; now you just want server names in file 0!

Please take a LARGE step back, look at the data you want to process, show us a representative sample of the data you want to process *using CODE tags), show us all of the corresponding output files that should be produced from that sample input (all using CODE tags), and provide a simple English description of the logic that determines how the input file is supposed to be transformed into the various output files.
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