Shell Programming and Scripting

Hello to all,

Maybe someone could help me, my question is:

How can a filter the print of command ls for the files with names of the form "abc*.txt" including the path?

I've done this:

If I move with command cd to /My/Path/Is/This/ and send this command:

Code:

ls -lst abc*.txt -i ?zabc*.txt

I get a filtered list containing files with names only with pattern abc*.txt and it seems to work fine.

But if I try to use the same command from another directory and including the path, the filtering is not working.

I've tried like this:

Code:

ls -lst abc*.txt -i ?zabc*.txt /My/Path/Is/This/

and like this and doesn't apply the filter neither

Code:

ls /My/Path/Is/This/ -lst abc*.txt -i ?zabc*.txt

Thanks for any help.

* is not a feature of ls, * is something the shell does.

So when you do ?zabc*.txt in the current directory, the shell will parse that into a list of names to feed into ls -- which happens before ls even runs.

The shell will let you mash them together though. It'll even let you quote any parts of it which don't have *'s and stuff in them:

Code:

ls "/My/Path/Is/This/"?zabc*.txt

If all you need is the names, you don't need ls -- remember the shell does it, not ls.

Code:

for FILENAME in "/My/Path/Is/This/"?zabc*.txt
do
        echo "Got file name $FILENAME"
done

Hello Corona688,
Thanks for your help. Actually I need the filename, date, hour, size etc, like what "ls -lt" gives.
I've modified your code to:

Code:

for FILENAME in "/My/Path/Is/This/"?zabc*.txt
do
        ls -lt "$FILENAME"
done

The only thing is that is printing the file with the path like this:

Code:

-rw-r--r-- 1 ri xyz  1048 Aug 11 05:15 /My/Path/Is/This/abc-dfe.txt

How to print the file without the path?, like this:

Code:

-rw-r--r-- 1 ri xyz  1048 Aug 11 05:15 abc-dfe.txt

Thanks again.

Best regards

You don't need the for loop if you're feeding it into ls, use my other example.

Code:

cd /path/to/folder ; ls *.whatever

Thank you Corona,

It works like this:

Code:

cd /path/to/folder ; ls *.whatever; cd-

The last issue it seems to be that if I use the pattern abc*.txt I get filenames like 123abc-yue.txt or 01xabc-oie.txt.

How to get only files that begin with "abc"?

Thanks again

You don't, unless you want to put the output through a text filter to get rid of it.

Thank you Corona,

It works like this:

Code:

cd /path/to/folder ; ls *.whatever; cd-

The last issue it seems to be that if I use the pattern abc*.txt I get filenames like 123abc-yue.txt or 01xabc-oie.txt and I would like only those that begins with abc.

How to get only files that begin with "abc"? It could be done modifying the pattern only?

Thanks again