Shell Programming and Scripting

Hi,

I have 3 fields in a file. For example I have them like this:
1,Santosh, 24

I want to have these 3 values in 3 different variables. How can I do it.

Thanks in advance

Using awk:

first=awk -F "," '{print $1}'
second=awk -F "," '{print $2}'
third=awk -F "," '{print $3}'

Using shell:

Code:

#!/usr/bin/ksh

oldIFS=$IFS
IFS=$IFS,
while read first second third; do
        echo $first $second $third
done < test
IFS=$oldIFS

Code:

# cat test
1,abc,24
2,def,25
3,pqr,40
# ./test.sh
1 abc 24
2 def 25
3 pqr 40

Hi,

Since my file that has got input values in the format "1,Mani,23" and I dont know how many such inputs are going to be there.I wrote the following script to print How many however values were there in the file:

while read line
do
count=1
more values | awk '{print $count}'
count=`expr $count + 1`
done < values

It gives me an error as following:
awk: Field $() is not correct.

How can print all the values in the file field by field ie...

if inputs are like this
1,Mani,23
2,San,24,
3,Tom,25
..
..
and so on. How can I print the first field,2nd field and the third field seperately using awk in a loop

Thanx in advance

can u give a sample output as well

Hi,
The format of the output should be:
1
2
3

Mani
San
Tom

23
24
25

You cannot use shell variables inside an awk command directly. Read up on awk programming to know how to do this. And since you are so keen on using awk to read the variables, try this:

Code:

#!/usr/bin/ksh

awk -F',' '{print $1," ",$2," ",$3}' test|while read first second third; do
   echo $first $second $third
done