awk print odd values


 
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# 1  
Old 07-25-2014
awk print odd values

Code:
value=$(some command)

for all in `echo $value`
do
    awk checks each value (all) to see if it is a odd number. if so, prints the value
done

sounds easy enough but i've been unable to find anything on google.
# 2  
Old 07-25-2014
awk can use modulus 2 and if result is 0 it's even:

Code:
$ echo "12" | awk "$0%2"
$ echo "13" | awk "$0%2"
13

But, do you really need to use awk this can be achieved from within the shell:

Code:
for all in 2 3 4 5 6
do
   [ $((all%2)) -gt 0 ] && echo $all
done

This User Gave Thanks to Chubler_XL For This Post:
# 3  
Old 07-25-2014
In recent shells, you could even simplify that to
Code:
for all in 2 3 4 5 6; do ((all%2)) && echo $all; done

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