Append next line to previous lines when NF is less than 0


 
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# 1  
Old 04-16-2014
Append next line to previous lines when NF is less than 0

Hi All,

This is very urgent, I've a data file with 1.7 millions rows in the file and the delimiter is cedilla and I need to format the data in such a way that if the NF in the next row is less than 1, it will append that value to previous line.

Any help will be appricated.

Thanks,
cumeh1624

---------- Post updated at 10:50 PM ---------- Previous update was at 10:46 PM ----------

I will prefer any suggestion using awk command because of performance

Last edited by cumeh1624; 04-16-2014 at 12:49 AM.. Reason: add more comments
# 2  
Old 04-16-2014
Quote:
Originally Posted by cumeh1624
if the NF in the next row is less than 1, it will append that value to previous line.
By NF < 1, do you mean the row is empty? (a blank line, perhaps)
# 3  
Old 04-16-2014
Code:
 awk '{printf "%s",(NF>0?$0:"\n")}' filename

# 4  
Old 04-16-2014
It means the very line has one field without cedilla as a field seperator or it has a blank line.
# 5  
Old 04-16-2014
Code:
awk 'BEGIN{FS='Ç'}
  NR == 1 {p = $0; next}
  NF > 1 {print p; p = $0}
  NF <= 1 {p = (p " " $0)}
  END {print p}' input.txt > output.txt

# 6  
Old 04-16-2014
Hi Srinishoo,

The script works fine but there is a limitation to it. I tested it with 1.7 million rows in a data file and about 10,471 rows with numerical values and some few characters with 5 to 9 fields didn't get loaded into the output file.

So when processing the files this statement "
Code:
NF > 1 {print p; p = $0}

" didn't send about 10,471 rows to the output file and the only different with other rows is that it contain almost numerica values in most of the column fields.

This is examplle of what one of the row that didn't get loaded looks like

Code:
29863Ç890000000Ç543209911ÇCHNGOHGÇ000000001Ç055Ç

do you hav a suggestion in handling this issue?

Last edited by Scrutinizer; 04-17-2014 at 06:25 AM.. Reason: code tags
# 7  
Old 04-17-2014
That should not be the case. Try the below code
exchanged single quotes with double quotes for FS assignment.

Code:
awk 'BEGIN{FS = "Ç"}
  NR == 1 {p = $0; next}
  NF > 1 {print p; p = $0}
  NF <= 1 {p = (p " " $0)}
  END {print p}' input.txt > output.txt

The number of rows will change between input and output as you are append few lines to previous line
and verify if both the input has the row you have provided
Code:
awk '$0 ~ /29863Ç890000000Ç543209911ÇCHNGOHGÇ000000001Ç055Ç/' input.txt
awk '$0 ~ /29863Ç890000000Ç543209911ÇCHNGOHGÇ000000001Ç055Ç/' output.txt

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