Shell Programming and Scripting

Hi all,

I have a script which should take more than 9 command line inputs while running. Like

Code:

script.sh a s d f g h j j k l o p i u y t r e w

Now in the script if I have to access one of the input which is at position after 9, in this case say 'p' then how can I do that?

Code:

echo $12

will not work as 1 & 2 would be taken as two independent numbers. I found a suggestion to mention

Code:

echo ${12}

but I guess it is for Bourne shell and for me on Korn shell it it is giving error as: script.sh: bad substitution

Can you please help me on this or direct me to a place when I can get more information.

Thanks,
Pat

That should work on any POSIX-compliant shell, including ksh (unless it's quite old). What's your OS?

It's SunOS 5.8 on UNIX server. Should {} work here

Code:

#!/bin/ksh
i=1
for arg in $*
do
  eval param$i=$arg;
  i=$(($i + 1))
done

echo $param12

${12} worked in the Bourne shell and has been supported by all versions of ksh since day 1.

Please show us your entire script, the command line you're using to invoke your script, and the EXACT diagnostic message you're getting when you run it.

Thank you for your input everyone. I am trying this and the output is also pasted here.

Code:

/export/home/pj317q> cat displayname.sh
echo $1
echo $2
echo $9
echo ${15}
echo ${10}
/export/home/pj317q> sh displayname.sh a b c d e f g h I j k l m n o p q r s t u v
a
b
I
displayname.sh: bad substitution
/export/home/pj317q>

Not sure whats going wrong.

Hi,
A solution:

Code:

$ /usr/bin/sh
$ set A B C D E F G H I J K L M N O P Q R S
$ echo $#
19
$ echo $19
A9
$ echo ${19}
bad substitution
$ echo $9
I
$ shift 10
$ echo $9
S

Regards.