How to print in the new line?


 
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Top Forums Shell Programming and Scripting How to print in the new line?
# 1  
Old 09-13-2013
How to print in the new line?

I have written below script for the output:

Code:
1234
123
12
1


Code:
" {
 read x
 y=$x
 i=1
 while [ $i -le $x ]
 do
 j=1
 while [ $j -le $y ]
 do
 if [ $i == 1 ]
 then
 print -n $j
 fi
 j=`expr $j + 1`
 done
 i=`expr $i + 1`
 y=`expr $y - 1`
 done
 }"

However, I am getting o/p horizontally: 1234123121

Can anyone please help?
# 2  
Old 09-13-2013
What o/p do you expect? Example
# 3  
Old 09-13-2013
Quote:
Originally Posted by Jotne
What o/p do you expect? Example
Hi there,

I got O/p from the above script as:

Code:
1234123121

I want it to be as shown below:

Code:
1234
123
12
1

Plz advise !!!

Last edited by Scott; 09-13-2013 at 10:45 AM.. Reason: Code tags
# 4  
Old 09-13-2013
Using awk
Code:
echo "4" | awk '{for (j=$0;j>=1;j--) {for (i=1;i<=j;i++) printf i; print ""}}'
1234
123
12
1

# 5  
Old 09-13-2013
Code:
{
   read x
   y=$x
   i=1
   while [ $i -le $x ]
   do
      j=1
      while [ $j -le $y ]
      do
         echo -n $j
         j=`expr $j + 1`
      done
      echo
      i=`expr $i + 1`
      y=`expr $y - 1`
   done
}

I have replaced the prints with echos and indented for reading purposes. YOu had an if construct which I assume you put in for debugging purposes.

Andrew
# 6  
Old 09-13-2013
Quote:
Originally Posted by Jotne
Using awk
Code:
echo "4" | awk '{for (j=$0;j>=1;j--) {for (i=1;i<=j;i++) printf i; print ""}}'
1234
123
12
1


Shell should take input from the user instead of assuming it to be "4"

---------- Post updated at 08:44 AM ---------- Previous update was at 08:41 AM ----------

Quote:
Originally Posted by apmcd47
Code:
{
   read x
   y=$x
   i=1
   while [ $i -le $x ]
   do
      j=1
      while [ $j -le $y ]
      do
         echo -n $j
         j=`expr $j + 1`
      done
      echo
      i=`expr $i + 1`
      y=`expr $y - 1`
   done
}

I have replaced the prints with echos and indented for reading purposes. YOu had an if construct which I assume you put in for debugging purposes.

Andrew

I should have quoted that I am working in KORN shell. I don't know how much implications it has on the syntax, but here is the O/P of your amended script.

Code:
3
-n 1
-n 2
-n 3

-n 1
-n 2

-n 1


Plz advise !

Last edited by Scott; 09-13-2013 at 10:46 AM.. Reason: Code tags
# 7  
Old 09-13-2013
Quote:
Originally Posted by targetshell


I should have quoted that I am working in KORN shell. I don't know how much implications it has on the syntax, but here is the O/P of your amended script.

Code:
3
-n 1
-n 2
-n 3

-n 1
-n 2

-n 1

Plz advise !
It works for ksh93 on Linux for me. Try putting the prints back in instead of the echos. What system are you running this on?

Andrew
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