[Solved] CSV to CSV MS-DOS


 
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# 8  
Old 03-14-2013
So it's basically CSV already, but the last column is a problem. OK. You can tell awk "substitute / for , in the very last column". You can also tell it 'print \r\n at the end of lines' so you don't need unix2dos after:

Code:
awk '{sub(/\//, ",", $NF)} 1' FS="," OFS="," ORS="\r\n" inputfile > outputfile

# 9  
Old 03-14-2013
Thanks Corona. But as I said, there's many columns (way too many to paste here) and several of them have the format xxx/xxx, not just the last column. It just needs to ignore column 2 and change the delimiter everywhere else.

Thanks
# 10  
Old 03-14-2013
Isn't that column 4?

Code:
awk '{sub(/\//, ",", $4)} 1' FS="," OFS="," ORS="\r\n" inputfile > outputfile

# 11  
Old 03-14-2013
Correct, column 4 in the sample input. However, it also applies to columns 8, 12, 16, 20, etc.
# 12  
Old 03-14-2013
In a regular pattern? Every 4 columns?

Code:
awk '{for(N=4; N<=NF; N+=4) sub(/\//, ",", $N) } 1' FS="," OFS="," ORS="\r\n" inputfile > outputfile

This User Gave Thanks to Corona688 For This Post:
# 13  
Old 03-15-2013
Correct.

---------- Post updated 03-15-13 at 07:06 AM ---------- Previous update was 03-14-13 at 11:50 AM ----------

Thanks, works just fine.
This User Gave Thanks to shadyuk For This Post:
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