UNIX :renaming the files present in the directory


 
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# 1  
Old 03-07-2013
UNIX :renaming the files present in the directory

Hi all,

I am looking for a script which renames all the files from the present directory.

Eg.:
In unix directory contains the below files

Code:
linux001.txt
linux002.txt
linux003.txt
......
.......

Now the files should be renamed to
Code:
unix001.txt
unix002.txt
unix003.txt

Could anyone please help me on the above requirement.

Thanks in advance...

Regards,
J

Last edited by Scrutinizer; 03-07-2013 at 05:59 AM.. Reason: code tags
# 2  
Old 03-07-2013
its a sample code..try with relevant names/paths. use the mv command instead.


Code:
for i in `seq -f 'linux%03.f.txt' 1 100`; do  echo $i; echo $i|awk '{ gsub(/^linux/,"unix",$0);print}'; done

---------- Post updated at 03:20 PM ---------- Previous update was at 03:18 PM ----------

Code:
for i in `seq -f 'linux%03.f.txt' 1 100`; do  mv $i  `echo ${i/linux/unix}`; done

# 3  
Old 03-07-2013
Code:
for i in linux*.txt
do
cp -p "$i" unix"${i#*x}" && rm "$i"
done

# 4  
Old 03-07-2013
busyboy is on the right track! Try
Code:
$ for i in linux*; do echo mv $i ${i/linux/unix}; done
mv linux001.txt unix001.txt
mv linux002.txt unix002.txt
mv linux003.txt unix003.txt

Remove echo if happy with results.
# 5  
Old 03-07-2013
Hello everybody,

I'm still a newbie, but here's my attempt:

$ for i in * ; do mv $i uni${i##linu}; done
This User Gave Thanks to mr.zeratul For This Post:
# 6  
Old 03-07-2013
Code:
# i=linux001.txt
# echo $i
linux001.txt
# echo ${i#*x}
001.txt
# echo unix${i#*x}
unix001.txt
#

# 7  
Old 03-07-2013
please run and let me know.

#! /bin/bash
list=(`ls`);
j=0;
len=${#list[*]};
while [ $j -lt $len ]
do
mv ${list[$j]} $(echo ${list[$j]} | sed 's/linux/unix/g');
j=`expr $j + 1`;
done
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