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How to pass filename as arguement to awk command?

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# 1  
Old 05-06-2013
Question How to pass filename as arguement to awk command?
Hi,
I am facing one issue. The awk command works fine if i hardcode the file name but if is pass it as an arguement it doesn't work. For e.g:Below commands works fine

Code:
awk -v A="$type" '{F=substr($0,23,8) "_LTD_" A ".txt"; print $0 >> F; close(F) }' RL004.txt

But the below command does not work.
Code:
awk -v A="$type" '{F=substr($0,23,8) "_LTD_" A ".txt"; print $0 >> F; close(F) }' $path/$filename

Can you please help with this.
Last edited by Scott; 05-06-2013 at 04:23 AM.. Reason: Please use code tags
# 2  
Old 05-06-2013
What do echo $path and echo $filename say? What error message do you get when you run the awk command?
# 3  
Old 05-06-2013
Earlier I wasn't getting any error, just that splitted files were not getting created.

The command worked fine once i ran the command after going to the directory where the file is present. It is not getting executed from any other path
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