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sed to replace specific positions on line with file contents

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# 1  
Old 02-22-2013
sed to replace specific positions on line with file contents
Hi, I am trying to use an awk command to replace specific character positions on a line beginning with 80 with contents of another file.

The line beginning with 80 in file1 is as follows:

Quote:
80................................000000000178800.000010........................
I want to replace the 000000000178800 (positions 34 - 49) on this file with the contents of amended_file_01 -> 000000000206100

The command i am using is:

Quote:
sed '/^80/s/\(^.\{34\}\).\{15\}\(.*\)/\1$amended_file01\2/' file1
The output from this command should be
Quote:
80................................000000000206100.000010........................
But it is returning the filename instead of the file contents

Quote:
80................................$amended_file01.000010........................
How would i get the command to return the file contents instead of the filename?
# 2  
Old 02-22-2013
I hope you have code to store the contents of file "amended_file_01" into variable "amended_file01"; after which a minor adjustment to your sed one-liner should do the trick:
Code:
sed "/^80/s/\(^.\{34\}\).\{15\}\(.*\)/\1$amended_file01\2/" file1

This User Gave Thanks to balajesuri For This Post:
nwalsh88
# 3  
Old 02-22-2013
Hi balajesuri,

That's perfect, thanks for your help
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