Scripting question


 
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# 1  
Old 02-04-2013
Scripting question

Hi
I am trying to write a small script which takes one by one file name from a txt file and do a 'll' and need to check if equal to the given month, otherwise it should return back the file name.
Note: the file name contains parameter.
My code is given below: It is not working .. giving error as no ll command found.

Code:
while read line
do

export File_Name=`eval echo $(echo $line)`

Month="(ll $File_Name | cut -d ' ' -f6)"

 if [ "$Month" = "Jun" ]
 then 
	echo "Correct"
 else
 	echo "$File_Name"
 fi

done<filecheck.dat

# 2  
Old 02-04-2013
Quote:
Originally Posted by Ravindra Swan
Code:
while read line
do
 
export File_Name=`eval echo $(echo $line)`
 
Month="(ll $File_Name | cut -d ' ' -f6)"
 
 if [ "$Month" = "Jun" ]
 then 
    echo "Correct"
 else
     echo "$File_Name"
 fi
 
done<filecheck.dat

Try using...

Code:
Month=$(ll $File_Name | cut -d ' ' -f6)

# 3  
Old 02-04-2013
Why do you use the eval echo construction, is it to condense spacing? Why not:

Code:
while read File_Name
do
  ...
done<filecheck.dat

# 4  
Old 02-04-2013
same error

No It is not working same error.

Code:
month.ksh: line 6: ll: command not found

# 5  
Old 02-04-2013
use ls -l instead of ll
# 6  
Old 02-04-2013
same error

Again i am getting same error
Code:
month.ksh: line 6: ls-l: command not found

---------- Post updated at 03:35 PM ---------- Previous update was at 03:32 PM ----------

Thanks got it
# 7  
Old 02-04-2013
You miss a space
wrong
Code:
ls-l

correct
Code:
ls -l

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