Shell Programming and Scripting

i have this below string which i need to convert it to HEX. i have already tried it but it showing extra few things on it.. let me show what i have done and what is the output i am getting and what is the desired output
the input string is

Code:

 
"!\"\"\"\"\"\"\"!\"\"\"\"\"\"\""

which is technically nothing but below

Code:

!"""""""!""""""""

so as for now consider that string is already present in variable myString

Code:

myString=$( echo $myString | sed 's/\\//g' )
#above command to strip \ in between '"'
 
len=${#myString}
cutString=${myString:1:$len-1}
#above command to strip additional '"' at first and last character.
 
echo $cutString
echo $cutString | xxd  -c 256 -ps
#above command to convert it to HEX

output obtained as of now is as below

Code:

21222222222222222122222222222222220a

BUT the actual output for

Code:

!"""""""!""""""""

should be

Code:

2122222222222222212222222222222222

32 characters.

as according to
any help on this is deeply appreciated. thanks

So the problem is the 0a? That's a ^J (newline).

Code:

echo $cutString | xxd  -c 256 -ps | sed "s/..$//"

so everytime that 0a will be a newline characters? so everytime i can just directly cut last 2 characters is it?

Yes, I guess so. I didn't see an xxd option to remove it.

It would not be there if you used printf instead of echo, actually.

Code:

printf $cutString | xxd  -c 256 -ps

oh okay.. got it.. its working as i wanted it... thanks a lot for the fix :-).