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Pass Parameters to awk command

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# 1  
Old 01-07-2013
Pass Parameters to awk command
I need to pass values at runtime for the below awk command where

l is the length and partial.txt is the file name.

Code:
 
awk -v l=285 '{s="%-"l"s\n";printf(s,$0);}' partial.txt > temp1.txt;

# 2  
Old 01-07-2013
Code:
FILE="partial.txt"
LEN=285

echo | awk -v l="$LEN" -v file="$FILE" '{s="%-"l"s\n"; while(( getline line < file  ) > 0 ) { print s,line; } } '

This User Gave Thanks to Yoda For This Post:
Amrutha24
# 3  
Old 01-07-2013
The parameters i need to pass are

FILE = <filepath>/partial.txt

When i replace the filepath it gives error as "cannot open the file for reading"
# 4  
Old 01-07-2013
It should work! Make sure you do not have any blank space between assignment operator = and wrap the string variable value in double quotes " to avoid any unexpected behavior.
# 5  
Old 01-07-2013
Code:
 
#!/bin/ksh
FILE=$1
LEN=$2
echo | awk -v l="$LEN" -v file="$FILE" '{s="%-"l"s\n";printf(s,$0);}' file > temp1.txt;

I execte the script using the below command

Code:
 
sh -x Script.sh /home/dhandal/partial.txt 285

Let me know whether i am executing right.
# 6  
Old 01-07-2013
Rather try
Code:
awk -v l="$LEN"  '{s="%-"l"s\n";printf(s,$0);}' $FILE > temp1.txt;

or
Code:
awk -v l="$2"  '{s="%-"l"s\n";printf(s,$0);}' $1 > temp1.txt;

Last edited by RudiC; 01-07-2013 at 02:40 AM.. Reason: Typo
This User Gave Thanks to RudiC For This Post:
Amrutha24
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