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How to Search string(which is in 2 lines) in a file?

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# 1  
Old 01-05-2013
How to Search string(which is in 2 lines) in a file?
Hello,

I want to search 2 lines from the file. I wanted to display all such matches. Example file:
==================
Code:
Testfile is test
TEST1
TEST2
testing the file string
to do testing
TEST1
TEST2
sample strings

=================
I wanted to search the file with 2 lines
"
Code:
TEST1
TEST2

"

Output should display (If possible, line numbers also )-
=====
Code:
TEST1
TEST2
TEST1
TEST2

============

Thank you
Last edited by Scrutinizer; 01-05-2013 at 05:41 AM.. Reason: code tags
# 2  
Old 01-05-2013
Assuming strings: TEST1 & TEST2 are in adjacent lines:
Code:
awk '$0=="TEST1"{getline;if($0=="TEST2") { print NR-1, "TEST1"; print NR, "TEST2"; } } ' filename

# 3  
Old 01-05-2013
Isn't that overly complicated? Try
Code:
$ awk '/^TEST[12]$/ {print NR,$0}' file 
3 TEST1
4 TEST2
7 TEST1
8 TEST2

BTW, the specification is not clear - do you want the lines of equals signs included or not? AND, pls use code tags as advised!

Oohhh - careful reading sometimes helps - you want the pattern to bspan two consecutive lines. Try this:
Code:
$ awk '/^TEST1$/{getline NL} NL~/^TEST2$/ {print  NR-1, $0; print NR, NL} NL=""' file
or
$ awk '/^TEST1$/{OL=NR FS $0; getline; if ($0~/^TEST2$/) {print  OL; print NR, $0}} ' file

Last edited by RudiC; 01-05-2013 at 05:49 AM.. Reason: Misread the request - correction
# 4  
Old 01-05-2013
Code:
sed -n '/TEST1/N; /\n.*TEST2/p' file

Line numbers:
Code:
nl -ba file | sed -n '/TEST1/N; /\n.*TEST2/p'

Last edited by Scrutinizer; 01-05-2013 at 06:00 AM..
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