Script with variable and condition


 
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# 1  
Old 12-27-2012
Script with variable and condition

Hello

newbies question...

I just need a script able to launch a command when a condition is matched :
Code:
#!/bin/ksh

SIZ = 'cat /nurp/control.lst|wc -l' 
if test "$SIZ" -gt 0
then
echo 1
else 
echo 2
fi

but I receive errors messages
Code:
./t2[5]: SIZ:  not found
2

whats wrong ?
thanks for help

Last edited by Franklin52; 12-28-2012 at 09:09 AM.. Reason: Please use code tags for data end code samples
# 2  
Old 12-27-2012
try sth like this..

Code:
SIZ=$(cat /nurp/control.lst|wc -l)
if [[ "$SIZ" -gt 0 ]]
then
echo 1
else
echo 2
fi

# 3  
Old 12-27-2012
A more simple version
Code:
SIZ=$(cat /nurp/control.lst|wc -l)
[[ "$SIZ" -gt 0 ]] && echo 1 || echo 2

# 4  
Old 12-27-2012
No need to use cat and variable SIZ:
Code:
[[ $( wc -l < infile ) -gt 0 ]] && echo 1 || echo 2

# 5  
Old 12-27-2012
Pls use code tags as advised.
All proposals above are fine and work, but I think your ./t2[5]: SIZ: not found error comes from the two spaces around the equals-sign when defining SIZ. Remove them, test, and come back with result.
# 6  
Old 12-27-2012
What RudiC mentioned is indeed an issue.

On top of that I see you are using single quote around the command:
Code:
'cat /nurp/control.lst|wc -l'

Replace that with:
Code:
SIZ=$( cat /nurp/control.lst|wc -l )

OR
Code:
SIZ=$( wc -l < /nurp/control.lst )

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